Challenging functions problem 1

Functions f and g are defined as follows:

Tex2Img_1403059512

Tex2Img_1403059582

Evaluate Tex2Img_1403059703

Solution

Tex2Img_1403059885

Tex2Img_1403059949

Tex2Img_1403060130

Tex2Img_1403060209

Therefore, both functions f and g repeat itself.

1994 divide by 3 has a remainder of 2. Therefore,

Tex2Img_1403060367

2011 divide by 3 has a remainder of 1. Therefore,

Tex2Img_1403060525

Leave a Reply

Please log in using one of these methods to post your comment:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google photo

You are commenting using your Google account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s

%d bloggers like this: