**2016 P1 Q7**

**Solution**

a) Hence part

Common methods to find the other root are long division or compare coef. A faster method is to use the sum of roots taught in additional maths.

b)

Comments from examiner’s report

Skip to content
# Category: Challenging questions

## Shortcut method for solving 2016 challenging complex number

## Range of probability values

## Challenging Probability Problem 7

## Challenging graphing technique question 1

## Top killer question in 2015 alevel

## Challenging Method of difference question 1

## Challenging System of Linear Equations Problem 2

## Challenging Alevel questions

## Challenging Probability problem 6

## Challenging Vector problem 4

**2016 P1 Q7**

**Solution**

a) Hence part

Common methods to find the other root are long division or compare coef. A faster method is to use the sum of roots taught in additional maths.

b)

Comments from examiner’s report

In 2015 alevel paper 2, finding the greatest and least possible probability values stumble many students. These examples will illustrate the methodology to solve such problems.

**Example 1: 2015 alevel P2, 9 iii**

**Solution**

**Example 2: 2014 AJC Prelim P2 Question 7iv **

**Solution**

**Part i**

**Part iv**

TJC JC2 Mar Common Test 2016

**Solution**

This question was posted by a student at Singapore JC maths.

**Solution for Part ii**

Many students viewed Paper 1, question 3 as the top killer question in the 2015 alevel h2 math 9740 paper.

This question is a new style of question in alevel, and is likely to come out in 2016 prelim and future Alevel.

The following questions serves as a good practise:

**Question 1**

Ans: 1.90235

**Solution**

**Question 2**

**Solution**

RVHS Promo 2014 Question 4:

Solution for the Hence portion:

Based on the alevel examiner’s report, these are the questions that were poorly done.

2018 P1: 6,9 iii, 10, 11

2018 P2: 6,7,9v

2017 P1: 5ii, 6, 7ii, 8, 9c, 11 iii

2017 P2: 1 ii, 2 ii, 3a, 4b, 7i, 9v, 9 vi

2016 P1: 3, 4, 6 iii, 7, 8 iii, 10 bii, 11 b

2016 P2: 2a ii, , 2b, 4bii, 7 iv, 9a

2015 P1: 3, 5 iii, 7iii, 11 ii explain why is maximum, 11 iii

2015 P2: 1 ii, 2ii, 3b, 4b iii (some students interpret wrongly), 9 ii, 9 iii, 10 iv, 11 iv

2014 P1: 2, 3, 4ii, 6 (a) (ii), 6 (b) (ii), 7 iii, 7 iv, 8 iii, 9 iii, 10 ii, 10 iv, 11 iii, 11 iv

2014 P2: 1 ii, 3 ii, 4 b ii, 6 ii, 6 iii, 10 ii

2013 P1: 2, 5, 6i, 6 iii, 8 i, 9 ii, 9 iii, 10 i, 10 iii, 11 ii, 11 iv

2013 P2: 1 ii, 2, 3 iii, 4iii, 6, 7 i, 8 iii, 9 i, 10 i, 11

2012 P1: 4, 5, 6 iii, 7 iii, 8 iii, 9 iii, 10, 11

2012 P2: 1 b, 3 ii, 3 v, 4, 6ii, 7 iii to v, 8 iii, 8 vii

2011 P1: 1, 3 iii, 4 i, 5 iii, 7 ii b, 8 c, 9 ii, 10 ii

2011 P2: 2 ii, 3 ii, 3 iii, 8 i, 9ii b, 10 iii, 11 ii

2010 P1: 1 ii, 6 iii, 6 iv, 7, 9, 10 i, 11 ii, 11 iii

2010 P2: 1 ii, 3 iii, 4v, 7iv, 7v, 8ii, 8iii, 10 iv

2009 P1: 1 ii, 2, 4, 10 iii, 11 iv

2009 P2: 1 i, 1 iii, 2 iii, 2 iv, 3, 4, 6 ii, 6 iii, 6 iv, 7, 8iii, 8iv, 9 iv, 11 i, 11 ii, 11 v

2008 P1: 1, 5 ii, 6a, 9 ii, 10 ii a, 10 ii b,

2008 P2: 1 iv, 2, 7, 8iii, 8 iv, 10 , 11 last part

2007 P1: 1, 2 i, 5 (hence part), 7i, 10 iii, 11

2007 P2: 2 iii, 2 iv, 3 iii, 4 ii b, 7 last part, 8, 9 (i) (b), 9 (ii) (c), 11

The owner of a restaurant counts the number of banquets received by the restaurant at the end of each week. The probability that the restaurant receives at least two banquets in a randomly chosen week is 0.3. A week is considered busy if the restaurant receives at least two wedding banquets in the week.

Calculate the probability that in a period of 6 consecutive weeks, the 6^{th} week is the second busy week, given that there is at most one busy week in the first four weeks.

Ans: 0.166

**Solution**

%d bloggers like this: