Challenging functions problem 1 Functions f and g are defined as follows: Evaluate Solution Therefore, both functions f and g repeat itself. 1994 divide by 3 has a remainder of 2. Therefore, 2011 divide by 3 has a remainder of 1. Therefore, Share this: Click to share on WhatsApp (Opens in new window) WhatsApp Click to share on Facebook (Opens in new window) Facebook Click to share on Telegram (Opens in new window) Telegram Click to share on X (Opens in new window) X Click to email a link to a friend (Opens in new window) Email Click to share on Reddit (Opens in new window) Reddit Like Loading... Related Published by gjooheng H2 maths tutor View all posts by gjooheng