Challenging functions problem 1 Functions f and g are defined as follows: Evaluate Solution Therefore, both functions f and g repeat itself. 1994 divide by 3 has a remainder of 2. Therefore, 2011 divide by 3 has a remainder of 1. Therefore, Share this: Share on WhatsApp (Opens in new window) WhatsApp Share on Facebook (Opens in new window) Facebook Share on Telegram (Opens in new window) Telegram Share on X (Opens in new window) X Email a link to a friend (Opens in new window) Email Share on Reddit (Opens in new window) Reddit Like Loading... Related Published by gjooheng H2 maths tutor View all posts by gjooheng