Challenging Permutation question 6 January 7, 2015February 12, 2017gjoohengLeave a Comment on Challenging Permutation question 6 RI H2 Math Permutations and Combinations Tutorial Section C (Challenging Questions) Alternative solution Number of different functions = number of ways to choose 3 distinct numbers from 0 to 9 = 10 choose 3 = 120 Share this:FacebookTwitterLike this:Like Loading... Related